A track is in the form of a ring whose inner and outer circumferences are 55 m and 132 respectively. Find the width of the track.
Answers
Answer:
A track is in the form of a ring whose inner and outer circumferences are 88 cm and 132 m respectively. Find the width of the track.
Step-by-step explanation:
Outer Circumference = 132 cm
=> Radius = Circumference / 2π
=> Radius = 132 / (2 × 22/7)
=> Radius = 132 / (44/7)
=> Radius = 132 × 7/44
=> Radius = 3 × 7
=> Radius = 21 cm
Inner Circumference = 88 cm
=> Radius = Circumference / 2π
=> Radius = 88 / (2 × 22/7)
=> Radius = 88 / (44/7)
=> Radius = 88 × 7/44
=> Radius = 2 × 7
=> Radius = 14 cm
Width of the ring = Outer Radius - Inner radius
= 21 - 14
= 7cm
.
.
Hope it will helps you ☺️
Answer:
For the inner track = Circumference = 55
c =2pie R
55= 2×22/7 × r
r= 8.75
Area Of outer track = Pie r²
= 22/7 × 8.75×8.75
= 240.62metres
For the outer track, Circumference = 132
132= 2×22/7 × r
r = 21m
Area = pie r²
= 22/7 × 21× 21
Area = 1387m
Width Of the track =
Area of Outer track - area of inner track
width = 1387-240.62
width = 1146metres