Question

a track is in the form of a ring whose inner and Outer circumference are 88 M and 132 M respectively find the width of the track

Answer 1

inner circumference =88m
2πr=88m
2×22/7×r=88m
22/7×r=88/2
r=44×7/22
r=14m
Area(1)=π×(r square)
=22/7×(14 square)
=22/7×14×14
=616m square.

outer circumference =132m
2πR=132m
2×22/7×R=132m
R×22/7=132m/2
R=66m×7/22
R=21m.
Area(2)=π×(R square)
=22/7×(21 square)
=22/7×21×21
=1386m square.

AREA OF TRACK=Area(2)-Area(1)
=(1386-616)m square
=770m square.

OK
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