A track is in the form of a ring whose inner outer circumference are 88 and 132.find the width of the track.
Answers
Answered by
20
inner circumference= 88
2πr=88
r=88/2π
outer circumference= 132
2πR=132
R=132/2π
width = R-r
=(132-88)/2π
=(44*7)/(2*22)
=7.
hope its the thing u were searching for....
2πr=88
r=88/2π
outer circumference= 132
2πR=132
R=132/2π
width = R-r
=(132-88)/2π
=(44*7)/(2*22)
=7.
hope its the thing u were searching for....
Soñador:
sahi kar diya answer
dekh lo
ok
ok bye bye
bye
bye bye 3
ok byeeeeeeee waise kis class me ho tum
8....
ooo you r my junior. ok it doesn't matter.
hmmm & u?
Answered by
5
find the radius of both by pie×r×2=circumference of each inner and outer circle. then find difference between the two radius. you will get the answer.
Similar questions