Question

A track of uniform path 2m wide runs around a rectangular field od 50m in lenght and 36m brradth. Find the area of track

Answer 1

HEY MATE HERE IS UR ANSWER

ITS GIVEN THAT -- THERE IS A RECTANGULAR FIELD OF LENGTH = 50 M AND BREADTH = 36M

AND THIS FIELD IS SURROUNDED BY A UNIFORM TRACK OF 2M . ( REFFER THE ATTACHMENT )

NOW WE NEED TO FIND THE AREA OF THIS TRACK.

THEREFORE

SOLUTION ➡️➡️IN THIS AREA OF TRACK WILL BE EQUAL TO AREA OF ABCD MINUS AREA OF PQRS

( REFFER THE PIC ).

NOW ACCORDING TO QUESTION ITS GIVEN THAT

LENGTH OF FIELD PQRS = 50 M

AND

BREADTH OF FIELD PQRS = 36 M

THEREFORE AREA OF FIELD PQRS IS LENGTH × BREADTH ( AS AREA OF RECTANGLE IS LENGTH ×

BREADTH)

THAT IS
$50m \times 36m = 1800 {m}^{2}$

THEREFORE AREA OF FIELD PQRS = 1800(m)^2

SO NOW AREA OF BIGGER RECTANGLE THAT IS AREA OF PQRS + AREA OF PATH OR TRACK ( ABCD )

ACCORDING TO QUESTION THE PATH IS HAVING UNIFORM WIDTH THAT IS = 2M

THEREFORE THE LENGTH OF BIGGER RECTANGLE ABCD IS

LENGTH OF PQRS + 2M IN BOTH LEFT AND RIGHT SIDE ( REFFER THE PICTURE)

THAT IS
$50m + 2m + 2m = 54m$
NOW BREADTH OF BIGGER RECTANGLE ABCD IS = BREADTH OF PQRS + 2M IN BOTH NORTH AND SOUTH

THAT IS

$36m + 2m + 2m = 40m \:$

SO NOW AREA OF BIGGER RECTANGLE IS

$(length \times breadth) = 54m \times 40m \: = 2160 {m}^{2}$

SO NOW AREA OF PATH OR TRACK IS

AREA OF ABCD - AREA OF PQRS

THAT IS
$2160 {m}^{2} - 1800 {m}^{2} = 360 {m}^{2}$

THEREFORE AREA OF PATH IS = 360 (M) ^2

HENCE THE ANSWER IS

$360 {m}^{2}$


➡️➡️HOPE IT'S HELPFUL IF YES PLEASE MARK AS BRAINLIEST ◀️◀️

BY ⏺️NIPUN ⏺️

BE BRAINLY ☯️

Answer 2

Answer:

HEY MATE HERE IS UR ANSWER

ITS GIVEN THAT -- THERE IS A RECTANGULAR FIELD OF LENGTH = 50 M AND BREADTH = 36M

AND THIS FIELD IS SURROUNDED BY A UNIFORM TRACK OF 2M . ( REFFER THE ATTACHMENT )

NOW WE NEED TO FIND THE AREA OF THIS TRACK.

THEREFORE

SOLUTION ➡️➡️IN THIS AREA OF TRACK WILL BE EQUAL TO AREA OF ABCD MINUS AREA OF PQRS

( REFFER THE PIC ).

NOW ACCORDING TO QUESTION ITS GIVEN THAT

LENGTH OF FIELD PQRS = 50 M

AND

BREADTH OF FIELD PQRS = 36 M

THEREFORE AREA OF FIELD PQRS IS LENGTH × BREADTH ( AS AREA OF RECTANGLE IS LENGTH ×

BREADTH)

THAT IS

THEREFORE AREA OF FIELD PQRS = 1800(m)^2

SO NOW AREA OF BIGGER RECTANGLE THAT IS AREA OF PQRS + AREA OF PATH OR TRACK ( ABCD )

ACCORDING TO QUESTION THE PATH IS HAVING UNIFORM WIDTH THAT IS = 2M

THEREFORE THE LENGTH OF BIGGER RECTANGLE ABCD IS

LENGTH OF PQRS + 2M IN BOTH LEFT AND RIGHT SIDE ( REFFER THE PICTURE)

THAT IS

NOW BREADTH OF BIGGER RECTANGLE ABCD IS = BREADTH OF PQRS + 2M IN BOTH NORTH AND SOUTH

THAT IS

SO NOW AREA OF BIGGER RECTANGLE IS

SO NOW AREA OF PATH OR TRACK IS

AREA OF ABCD - AREA OF PQRS

THAT IS

THEREFORE AREA OF PATH IS = 360 (M) ^2

HENCE THE ANSWER IS

➡️➡️HOPE IT'S HELPFUL IF YES PLEASE MARK AS BRAINLIEST ◀️◀️

BY ⏺️NIPUN ⏺️

BE BRAINLY ☯️

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