Question

A track starts from rest and roll down a hill with constant acceleration.it travels a distance of 400m in 20s .find its acclamation. also find the force acting on it if its mass is 7000 kg.​

Answer 1

Answer:

This will help you.

Explanation:

* Truck is at rest so, U= 0

* Distance = 400 m

* Time = 20 seconds

* So by 2 equation of motion

s =ut+1/2 a(t)2

= 400 =0+1/2 a(20)2

= 400 = 200a

= a = 2m/s2

Force = mass × acceleration

F= 7000×2

= 14000N

So, here is your answer..

Thanks