Question

A tractor is initially at rest and travels 200 m in 10 s with constant acceleration. Calculate the acceleration and final velocity at the end of 10 s.

Answer 1

Given :-

• Distance travelled by Tractor (S) = 200m
• Time taken by Tractor (T) = 10 Sec
• The initial velocity of tractor (u) = 0 m/s

To Find :-

• The acceleration of tractor = ?
• The final velocity of tractor = ?

Solution :-

• To calculate the acceleration and final velocity of the tractor at first we have to find acceleration then calculate it final velocity.

Calculation begins :-

• By using 2nd equation of motion :-

⇢ S = U × T + 1/2 × A × T²

⇢ 200 = 0 × 10 + 1/2 × A × 10²

⇢ 200 = 0 + 1/2 × 100A

⇢ 200 = 1/2 × 100A

⇢ 200 = 50A

⇢ A = 4 m/s²

Now we have here :-

• Acceleration (a) = 4 m/s²
• Initial velocity (u) = 0
• Time taken (t) = 10 Sec

By using 1st equation of motion :-

⇢ Final velocity (v) = U + A × T

⇢ Final velocity (v) = 0 + 4 × 10

⇢ Final velocity (v) = 0 + 40

⇢ Final velocity (v) = 40 m/s

Hence,

• The acceleration of tractor = 4m/s²
• The final velocity of tractor = 40 m/s

Answer 2

G I V E N :

A tractor is initially at rest and travels 200 m in 10 s with constant acceleration. Calculate the acceleration and final velocity at the end of 10s.

S O L U T I O N :

Gíѵєn tɦαt ⤵

A tractor is initially at rest it means that it's initial velocity should be zero

Initial Velocity (u) = 0 m/sec

It travels for 200 m for 10 s

Distance (S) = 200 m

Time (t) = 10 s

Tσ Fíղժ ⤵

• The final velocity at the end of 10 sec

• The acceleration of the tractor

____________________________________

Here, first we need to calculate the acceleration or a using the second equation of motion and get the value and then get the final velocity or v either using the first equation of motion or applying the third equation of motion. Here, we'll apply the third equation for getting the velocity.

Fíղdíng Accєlєrαtion ⤵

Using the second equation of motion we get

• S = ut + ½at²

Putting the values

• 200 = 0(10) + ½a(10)²

• 200 = 0 + 50a

• 50a = 200

• a = 200/50

• a = 4 m/s²

Hence, the acceleration (a) is 4 m/s²

Fíndíng Fínαl Vεløcíty ⤵

Using third equation of motion we get

• v² = u² + 2aS

• v² = (0)² + 2(4)200

• v² = 400(4)

• v² = 1600

Taking root on both the sides

• √v² = √1600

• v = 40

Henceforth, the velocity is 40 m/s