Question

A tractor is initially at rest and travels 300 m in 15 s with constant acceleration. Calculate the acceleration and final velocity at the end of 15 s.​

Answer 1

Answer:

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Answer 2

Answer:

Given Information,

• Distance Covered = 300 m
• Time Taken = 15 seconds
• Acceleration = Uniform (a)
• Final Velocity = (v)

To Find,

• Acceleration (a)
• Final Velocity (v)

Solution,

Using second equation of motion we get:

⇒ s = ut + 0.5 at²

⇒ 300 = 0 ( 15 ) + 0.5 ( a ) ( 15 )²

⇒ 300 = 0 + 112.5 (a)

⇒ a = 300 / 112.5

⇒ a = 2.67 m/s²

Hence the acceleration of the tractor is 2.67 m/s².

Calculating the Final velocity using first equation of motion we get,

⇒ v = u + at

⇒ v = 0 + (2.67) (15)

⇒ v = 40.05 m/s

Hence the final velocity of the tractor is 40.05 m/s.