A trader bought a number of articles for rs.900 . five articles were found to be damaged . he sold each of the remaining articles for rs.2 more than what he paid for it.he got a profit of rs.80 on the whole transaction . find the number of articles he had bought.
Answers
Answer:
75 Articles
Step-by-step explanation:
A trader bought a number of articles for rs.900 . five articles were found to be damaged . he sold each of the remaining articles for rs.2 more than what he paid for it.he got a profit of rs.80 on the whole transaction . find the number of articles he had bought.
Let Say Trader bought = X articles
He Paid Rs 900 in Total
Cost Price of one article = 900/X Rs
Damaged Articles = 5
Sell-able articles = X - 5
Selling Price = 900/X + 2 = (900 + 2X)/X Rs
Total Selling Amount = (X-5)((900 + 2X)/X) Rs
He got a profit of Rs 800
so total Selling Price = 900 + 80 = Rs 980
(X-5)((900 + 2X)/X) = 980
=> (X-5)(900 + 2X) = 980X
=> 2X² + 890X - 4500 = 980X
=> 2X² - 90X - 4500 = 0
=> X² -45X - 2250 = 0
=> X² -75X + 30X - 2250 = 0
=> X (X -75) + 30(X -75) = 0
=> (X+30)(X-75) = 0
=> X = 75 as Numbers of articles can be negative
So Trader Bought 75 Articles
Answer:
Step-by-step explanation:
Let the inner of articles be x
Let the cost of one article be a
Cost of article = x×a=900
a=900/x
According to the information
{x-5}{a+2}=900+80
xa-5a+2x-10=980
900-5×900/x+2x=990
2x-4500/x=90
X-2250/x=45
x^-45x-2250=0
Using splitting the middle term formula
a+b =-45. ab=-2250
Let a =-75 and b =30
-75+30=-45 and -75×30=-2250
{x^-75x}+{30x-2250}=0
x{x-75}+30{x-75}=0
{x-75}{x+30}
So x=75. OR. x=-30
Cost of one article = 900/x
=900/75
=Rs12