A trader bought certain number of articles for Rs. 3000. Three of the articles for damaged and he sold they rest at Rs. 65 more than what he paid for each and gained Rs. 180. Find the numbers of the articles bought by him.
Answers
Answer:
Let's see an example.
Step-by-step explanation:
A trader bought a number of articles for Rs. 900, five articles were found damaged. He sold each of the remaining articles at Rs. 2 more than what he paid for it. He got a profit of Rs. 80 on the whole transaction. Find the number of articles he bought.
Ans. Let the total number of articles be n.
Let the value of one article be a.
Given that trader bought n articles for Rs900.
So that n×a=900 and a=
n
900
Also given that five of them were damaged, he sold the remaining articles for Rs. 2 extra and he also got a Rs. 80 profit.
So that the equation would be (n−5)×(a+2)=900+80
⇒ na−5a+2n−10=980.
⇒ 900−5×
n
900
+2n=990 [∴ na = 900 and a = 900/n]
⇒ 2n−
n
4500
=90
⇒ n−
n
2250
=45
⇒ n
2
−2250=45n
⇒ n
2
−45n−2250=0
⇒ n
2
−75n+30n−2250=0
⇒ n(n−75)+30(n−75)=0
⇒ (n−75)(n+30)=0
⇒ n=75 or −30
Since n is the number of goods, it is always positive.
Hence, number of articles he bought was 75.
You solve this in your own.