Math, asked by raybarnali1993, 11 months ago

A trader claims to sell commodity at the loss of 6% but he uses 900gm weight instead of 1kg. How much percent is his actual price?

Answers

Answered by riteshkumar6480
0

Answer:


Step-by-step explanation:

Dishonest Dealer: A dishonest dealer is one who claims to sell his product in welfare of customer but either he alters weight or he marks up price too high and then gives discount to attract customers.

Let us assume that the shopkeeper makes a gain of G% in selling his product.

Therefore,

(100+G)/(100+x) = True weight/ False weight

Here,

G = Overall gain percentage

X = %loss or % gain

Also, another formula that you can remember, in case the shopkeeper sells at the cost price, is:

Gain Percentage

profit-and-loss-Discounts-and-Marked-Price-2

Let us check this formula by taking an example.

Let us say that I went to a shop to by 1kg almonds. The shopkeeper told me that he is selling the almonds at the cost price but he actually used a faulty weight and gave me only 800gm. Let the cost which the shopkeeper paid for 1 kg was Rs 1000 and as he told me that he is selling at the cost price so I will pay him Rs 1000 for 1kg. But what I am getting instead 1kg, only 800gm. Now try to understand the logic. The shopkeeper sold me 800 gm almonds for Rs 1000 for which he actually paid Rs 800 (cost price of 800gm). So he gained 1000 – 800 = Rs 200 and his percentage profit = (200/800)x100

which is same as given above in the formula. Here 200 is the error and 800 = 1000 – 200 = True weight – Error.

So how to proceed with the problems when the shopkeeper is selling the articles at a price different from that of cost price while using faulty weight? In this case the shopkeeper will make two profits. First profit is because of the wrong weight and the second is because of the actual difference between the cost price and the selling price. The final profit percentage is arrived by using the result {P + Q + (PQ/100)} where P and Q are the two profits.


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