Question

. A trader has 200 kg of sugar, out of which he sells some with 10% profit and the rest with 25% profit. He gains 15% on the whole. Find the quantity of sugar sold at 25% profit?
with explanation​

Answer 1

Step-by-step explanation:

Let CP of each kg. of sugar = Rs.1.

Cost Price of 200 kg of sugar = Rs.200.

Let quantity of sugar sold with 25% profit be X.

Therefore, (200 – X) kg of sugar sold at a profit of 10%

Then,

(125/100 * X) + 110/100 (200 – X) = 115/100 * 200

125X + 110(200 – X) = 115 * 200

125X + 22000 – 110X = 23000

125X – 110X = 23000 – 22000

15X = 1000

X = 1000/15

X = 66.66 kg

Quantity of sugar that was sold at 25% gain is 66.66 kg

Therefore, option nearby for 66.66 is 67

Hope its help..

Answer 2

Answer:

67 kgs

Step-by-step explanation:

Let CP of each kg. of sugar = Rs.1.

Cost Price of 200 kg of sugar = Rs.200.

Let quantity of sugar sold with 25% profit be X.

Therefore, (200 – X) kg of sugar sold at a profit of 10%

Then,

(125/100 * X) + 110/100 (200 – X) = 115/100 * 200

125X + 110(200 – X) = 115 * 200

125X + 22000 – 110X = 23000

125X – 110X = 23000 – 22000

15X = 1000

X = 1000/15

X = 66.66 kg

Quantity of sugar that was sold at 25% gain is 66.66 kg

Therefore, option nearby for 66.66 is 67 (d)