Question

a trader has three kinds of sugar , of the first 117 kgs.of the second 130 kgs and of third kind 143 kgs.the least number of full casks of equal size in which this can be stored without mixing is.
30
25
35
40
none​

Answer 1

Answer:

non

Step-by-step explanation:

I think this

if it is wrong I'm sorry

if I am correct brain list please

Answer 2

Answer:

The correct answer is Option A : $30$.

Step-by-step explanation:

We know that the $3$ kinds are :

Sugar I $= 117kg$

Sugar II $= 130kg$

Sugar III $= 143 kg$

To get the highest capacity of each container, we need to find the HCF of these $3$ numbers :

i.e. HCF of $117,130,143$ $=13$

To get the number of casks, we can divide the $3$ kinds of sugar by the HCF :

No. Of casks for sugar I : $\frac{117}{13} = 9$

No of casks for sugar II : $\frac{130}{13} = 10$

No. Of casks for sugar III : $\frac{143}{13} = 11$

So, the least number of casks required are $9+10+11=30$