Question

A trader has three types of oils of the following quantities: 406 liters, 434 liters and 455 liters respectively. if he wants to fill them separately in tins of equal capacity, what is the least number of tins required?

Answer 1

tin of 406 liters should be required

Answer 2

Answer:

The least number of tins required is 7.                  

Step-by-step explanation:

Given : A trader has three types of oils of the following quantities: 406 liters, 434 liters and 455 liters respectively. if he wants to fill them separately in tins of equal capacity.

To find : What is the least number of tins required?

Solution :

We have to find the HCF of 406 liters, 434 liters and 455 liters.

$406=2\times 7\times 29$

$434=2\times 7\times 31$

$455=5\times 7\times 13$

$HCF(406,434,455)=7$

Therefore, The least number of tins required is 7.