Question

. A trader mixes 2 kg of butter which costs
$8 per kg with 3 kg of butter which costs $6 per kg.
He sells the mixture at $2.55 per 250 g. Express his
profit as a percentage of his selling price.​

Answer 1

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✔️ Question:-

A trader mixes 2 kg of butter which costs $8 per kg with 3 kg of butter which costs $6 per kg. He sells the mixture at $2.55 per 250g. Express his profit as a percentage of his selling price.

✔️ Answer:-

Total cost of 2 kg butter @ $ 8 per kg = 8*2

= $ 16

Total cost of 3 kg butter @ $ 6 per kg = 6*3

= $ 18

Total cost of 5 kg butter = $ 16 + $ 18

= $ 34

Selling price = $ 2.55 per 250 g

Selling price of per kg = $ 2.55*4

= $ 10.2/kg

Selling price of 5 kg = 10.2*5

= $ 51

Profit = $ 51 - $ 34

= $ 17

Percentage on cost price = ($ 17*100)/$34

= 50 %

Percentage on selling price = ($ 17*100)/$51

= 33.33 %

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Answer 2

Given:-

• C.P. of butter = $8 per kg
• Quantity of butter used = 2kg
• C.P. of other quality of butter = $6 per kg
• Quantity of other quality butter = 3kg
• S.P. of mixture of butter = $2.55 per 250 g

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To Find:-

• Total Profit percentage

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Formula Used:-

• Profit = S.P. - C.P.

• Profit % = {(Profit ÷ C.P.) × 100}%

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Solution:-

Finding total C.P. of mixture:

➥ C.P. of 2 kg of butter

= 2 × $8

= $16

➥ C.P. of 3 kg of other quality of butter

= 3 × $6

= $18

➥ Total C.P. of mixture

= $16 + $18

= $34

Finding total s.p. of mixture:

➥ Total Amount of mixture

= 2 + 3

= 5kg

➥ Cost of 1 kg of mixture

= $2.55 × (1000 ÷ 250)

= $2.55 × 4

= $10.2

➥ Total cost of mixture

= 5 × $10.2

= $51

Finding profit percentage:

➥ Profit

= S.P. - C.P.

= 51 - 34

= 17

➥ Profit Percentage on cost price

= {(Profit ÷ C.P.) × 100}%

= {(17 ÷ 34) × 100}%

= {100 ÷ 2}%

= 50%

➥ Profit Percentage on selling price

= {(Profit ÷ S.P.) × 100}%

= {(17 ÷ 51) × 100}%

= {100 ÷ 3}%

= 33.3%

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Answer:-

▪︎Total Profit percent on s.p. is 33.3%.

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