Math, asked by vinayprabhas1533, 1 year ago

A trader purchase 180 bags of cement at 900 rupees per bag. he sold 70 bags at 20% profit and 50 bags at 6% loss

Answers

Answered by dishantraj2004
0

Answer:

Step-by-step explanation:

He purchased bags at ₹900 each and sold 70 bags at 20% profit hece he sold 70 bags at

20÷100×900=180

And 900+180= 1080

And 1080×70=75600

Now,

50 bags at 6% loss hence

6÷100×900=54

900-54=816

50×816=40800

75600-40800=34800

Answered by nishantgour007
1

Answer:

963 rs per bag

Step-by-step explanation:

remaining bags are 180-70-50 = 60 bags left.

let the loss or gain % = x %

gain/loss % percentage = (sum of product of quantity and respective gain/loss% )/Amount of whole property

9 = (70*20 + 50*-6 + x*60)/180

x = +7%

cost price = Rs 900 per bag  = 7%

sale price  = 107/100*900 = 963 rs per bag

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