Question

A trader purchases a watch and a wall clock for 390 rupees. He sell them making a profit of 10 % on the watch and 15% on the wall clock. He earns a profit of 51.50 rupees. The difference between the original prices of the wall clock and the watch is equal to ​

Answer 1

Answer:

$\huge\underline\bold {Answer:}$

Let the cost of the watch = x rupees. Then,

Cost of the clock = (390 – x)

Given, 10% of x + 15% of (390 – x) = 51.50

=>x/10 + 15 × (390 – x) = 51.50

=> x/10 + {15 × (390 – x)} ÷ 100 = 51.50

=> 10x + 5850 – 15x = 5150

=> 5x = 700

=> x = 140

Therefore, watch of clock = (390 – 140) = 250 rupees.

Therefore, required difference = 250 – 140

= 110

So the difference between the original prices of the wall clock and the watch is equal to 110 rupees.

Answer 2

ANSWER

Let the cost of the watch = Rs. x.

Then, cost of the clock = Rs. (390−x)

Given, 10% of x+15% of (390−x)=51.50

⇒

10

x

+

100

15×(390−x)

=51.50

⇒10x+5850−15x=5150

⇒5x=700

⇒x=140

∴ Cost of clock = Rs. (390−140)= Rs. 250

∴ Required difference = Rs. 250−Rs. 140=Rs. 110.

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