A trader purchases a watch and a wall clock for 390 rupees. He sell them making a profit of 10 % on the watch and 15% on the wall clock. He earns a profit of 51.50 rupees. The difference between the original prices of the wall clock and the watch is equal to
Answers
Answered by
1
Answer:
Let the cost of the watch = x rupees. Then,
Cost of the clock = (390 – x)
Given, 10% of x + 15% of (390 – x) = 51.50
=>x/10 + 15 × (390 – x) = 51.50
=> x/10 + {15 × (390 – x)} ÷ 100 = 51.50
=> 10x + 5850 – 15x = 5150
=> 5x = 700
=> x = 140
Therefore, watch of clock = (390 – 140) = 250 rupees.
Therefore, required difference = 250 – 140
= 110
So the difference between the original prices of the wall clock and the watch is equal to 110 rupees.
Answered by
4
Answer:
Let the cost of the watch = Rs. x.
Then, cost of the clock = Rs. (390−x)
Given, 10% of x+15% of (390−x)=51.50
- x/10 + 15 × ( 390 - x ) / 100 = 51.50
- 10x + 5850 - 15x = 51.50
- 5x = 700
- x= 140
- ∴ Cost of clock = Rs. (390−140)= Rs. 250
- ∴ Required difference = Rs. 250−Rs. 140=Rs. 110.
Step-by-step explanation:
hope this helps you..
Similar questions