Math, asked by Alrightboi, 7 months ago

A trader purchases a watch and a wall clock for 390 rupees. He sell them making a profit of 10 % on the watch and 15% on the wall clock. He earns a profit of 51.50 rupees. The difference between the original prices of the wall clock and the watch is equal to ​

Answers

Answered by Anonymous
2

Answer:

\huge\underline\bold {Answer:}

Let the cost of the watch = x rupees. Then,

Cost of the clock = (390 – x)

Given, 10% of x + 15% of (390 – x) = 51.50

=>x/10 + 15 × (390 – x) = 51.50

=> x/10 + {15 × (390 – x)} ÷ 100 = 51.50

=> 10x + 5850 – 15x = 5150

=> 5x = 700

=> x = 140

Therefore, watch of clock = (390 – 140) = 250 rupees.

Therefore, required difference = 250 – 140

= 110

So the difference between the original prices of the wall clock and the watch is equal to 110 rupees.

Answered by Anonymous
2

Given :

  • A trader purchases a watch and a wall clock for 390 rupees. He sell them making a profit of 10 % on the watch and 15% on the wall clock. He earns a profit of 51.50 rupees.

To find :

  • What is the difference between the original prices of the wall clock and the watch is equal to.

Calculations :

→ x/10 + 15 (390 - x)/100 = 51.50

→ 10x + 5850 - 15x = 5150

→ 5x = 700

→ 700/5x

→ 140

Let's, substitute the above equation :

→ 390 - 140

→ 250

Therefore, the cost of the clock is equal to 250.

→ 250 - 140

→ 110

Therefore, 110 is difference between the original price of the wall clock.

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