Math, asked by kishormevcha, 9 months ago

A trader puts 100 rupees in seven bags in such a way that he can pay any amount from 1 to 100 without leaving the bag. So how many rupees would have been put in the bag​

Answers

Answered by SHREY1620T
1

Answer:

the solution is:

We have 1000 coins and this being even number, we simply divide this by 2 and get the 1st quotient, which is

1st Quotient is 500 and 1000 – 500 = 500

2nd quotient is 250 and 500 - 250 = 250

3rd quotient is 125 and 250 - 125 = 125 and being odd we consider it 126

4th quotient is 63 and 125 - 63 = 62

5th quotient is 31 and 62 - 31 = 31 and being odd we consider it 32

6th quotient is 16 and 31 - 16 = 15 and being odd we consider it 16

7th quotient is 8 and 15 - 8 = 7 and being odd we consider it 8

8th quotient is 4 and 7 - 4 = 3 and being odd we consider it 4

9th quotient is 2 and 3 - 2 = 1 and being odd we consider it 2

10th quotient is 1 and 1 - 1 = 0 and we come to the end of the solution.

Thus, here goes the way to divide 1000 coins into 10 Bags containing

500, 250, 125, 63, 31, 16, 8, 4, 2 and 1 coins.

500+250+125+63+31+16+8+4+2+1 = 1000.

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