Math, asked by royavrajoty100, 7 months ago

A trader sales two horses. One in 15% gain and another one in 8% loss. He sales the horses for 1440.what are the cost prices of the horses??​

Answers

Answered by patelarya302
0

Answer:

Solutions :-

We have

A man sold of two horses for Rs 29700 each.

Cost Price of one horse at 10% loss = (S.P × 100)/(100 - loss)

= (29700 × 100)/(100 - 10)

= 2970000/90

= 33000

Cost Price of other horse at 10% gain = (S.P × 100)/(100 + gain)

= (29700 × 100)/(100 + 10)

= 2970000/110

= 27000

Total cost price of two horses = Rs (33000 + 27000) = Rs 60000

Total selling price of two horses = Rs (29700 + 29700) = Rs 59400

Selling price < Cost Price

Loss = S.P - C.P

= Rs (60000 - 59400)

= Rs 600

Loss % = (loss × 100)/C.P %

= (600 × 100)/60000 %

= 60000/60000 %

= 1 %

Answer : Total loss percent in the transaction = 1%

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