Math, asked by medavarapuasritha, 6 months ago

A trader sells articles X and Y for INR 480 each with no loss or profit in the whole transaction. If A is sold at
16- % loss, then B is sold at a profit of​

Answers

Answered by ds454676
0

Step-by-step explanation:

trader sells A = 480×16÷ 100 = 384÷5 = 76.8

480- 76 = 404

B= 480+76= 556

profit persentage= 76×100÷480= 380÷24 = 15.8333

Answer

Answered by amitnrw
2

Given : A trader sells articles X and Y for INR 480 each with no loss or profit in the whole transaction

A is sold at  16- % loss,

To Find :  B is sold at a profit of​

Solution:

A trader sells articles X and Y for INR 480 each

-> Total Sell price = 480 + 480 = 960   Rs

Total Cost Price = 960 Rs

As no loss or profit   in the whole transaction.

A Cost Price   = A    Rs  then B cost Price  = 960 - A  Rs

Loss on A = 16  %

SP of A = A - (16/100)A = 0.84A  Rs

=>  0.84A  = 480

=> A = 480/0.84  =  4000/7

SP of B = 960 -  0.84A   Rs

Profit on B = 960 -  0.84A - (960 - A)  = 0.16A

Profit %  = 100  *  0.16A / ( 960 - A  )  

= 16A / ( 960 - A)

=( 16 * 4000/7 ) / ( 960- 4000/7)

= 16 * 4000 / 2720

= 23.53 %

B is sold at a profit of​ 23.53 %

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