Math, asked by selenamarquez4061, 11 months ago

A trader sells one type of sugar at 10 rupees per
kg. and suffered a loss of 20%. While he sells
the other type of sugar at Rs. 15 per kg and
makes a profit of 25%. Now he mixes both type
of sugar in equal proportion and sells the mix-
ture at 18 rupees per kg. Find his profit and loss
now

Answers

Answered by vivek4747
0

Answer:

hope it will be helpful for you

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Answered by FelisFelis
0

The profit is 46\dfrac{46}{49}\ or\ 46.94\%.

Step-by-step explanation:

Consider the provided information.

A trader sells one type of sugar at 10 rupees per  kg. and suffered a loss of 20%. While he sells.

The cost price of sugar was: \frac{10}{80}\times100 =12.5

The other type of sugar at Rs. 15 per kg and  makes a profit of 25%. Now he mixes both type.

The cost price of other type of sugar was: \frac{15}{125}\times100 =12

It is given that trader sells mixture at 18 rupees per kg.

The cost price of 2 kg of sugar is: 12.5+12=24.5 rupees.

The selling price of 2 kg of sugar is: 18×2 =36 rupees.

Thus, the profit is: 36-24.5=11.5  ruppes.

The profit% is: \frac{11.5}{24.5} \times100=46\dfrac{46}{49}\ or\ 46.94\%

Hence, the profit is 46\dfrac{46}{49}\ or\ 46.94\%.

#Learn more

10. A man gains 20% by selling Apples at a certain price. If he sells it at Rs. 1.2 higher than the previous price he gains

40%. Find the original cost price.

(a) Rs. 5

(b) Rs. 8

(C) Rs. 6

(d) None of these

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