Math, asked by TheIron0man, 19 days ago

A trader sells three motorcycles for Rs 5400, Rs 3300 and Rs 5250 respectively. He gains 20% on the first motorcycle, 10% profit on the second and 25/8% loss on the total. Find the cost price of the third.

Answers

Answered by tennetiraj86
22

Step-by-step explanation:

Given :-

A trader sells three motorcycles for Rs 5400, Rs 3300 and Rs 5250 respectively. He gains 20% on the first motorcycle, 10% profit on the second and 25/8% loss on the total.

To find :-

Find the cost price of the third ?

Solution :-

The Selling Price of the first motorcycle

= Rs. 5400

Profit on it = 20%

We know that

Cost price = (100×SP)/(100+g)

=> CP = (100×5400)/(100+20)

=> CP = 540000/120

=> CP = 54000/12

=> CP = 4500

Cost price of the first motorcycle

= Rs. 4500

The selling price of the second motor cycle = Rs. 3300

Profit on it = 10%

We know that

Cost price = (100×SP)/(100+g)

=> CP = (100×3300)/(100+10)

=> CP = 330000/110

=> CP = 33000/11

=> CP = 3000

Cost price of the second motorcycle

= Rs.3300

The Selling Price of the third motorcycle

= Rs. 5250

Let the cost price of the third motorcycle be Rs. X

Total Selling prices of the three motorcycles = 5400+3300+5250

=> Rs. 13950

Total Cost prices of the three motorcycles = 4500+3000+X

=> Rs. (7500+X)

Given that

Loss on the whole translation = 25/8%

So, It is clear that

CP > SP

We know that

Cost price = (100×SP)/(100-l)

=> 7500+X = (100×13950)/[100-(25/8)]

=> 7500+X = 1395000/[(800-25)/8]

=> 7500+X = 1395000/(775/8)

=> 7500+X = (1395000×8)/775

=> 7500+X = 11160000/775

=> 7500+X = 14400

=> X = 14400-7500

=> X = 6900

Therefore, The Cost of the third motorcycle = Rs. 6900

Answer:-

The Cost Price of the third motorcycle is

Rs. 6900

Check :-

CP of three motorcycles

= Rs. 4500+3000+6900

=> 14400

SP of the three motorcycles = Rs. 13950

As we know ,Loss = CP-SP

=> Loss = 14400-13950

=> Loss = Rs. 450

Loss % = (Loss/CP)×100

=> Loss% = (450/14400)×100

=> Loss% = 450/144

=> Loss% = (25×18)/(8×18)

=> Loss% = 25/8

We get Loss% as 25/8% which is given in the problem.

Verified the given relations in the given problem.

Used formulae:-

→ Cost price = (100×SP)/(100+g)

→ CP = (100×SP)/(100-l)

→ Loss = Cost Price - Selling Price

→Loss % = (Loss/CP)×100

  • CP = Cost Price
  • SP = Selling Price
  • g = gain or profit
  • l = loss
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