Math, asked by pakoda23, 1 year ago

A trader sells two varieties of Rice A and B. He Mixes 12 Kg of A with 16 kg of B, and by selling this mixture at price of B Rice he gets 20% profit. If the price of A variety Rice is Rs.66/Kg, then what is the price of B variety /Kg.​

Answers

Answered by santy2
3

Answer:

Rs 108 per kg

Step-by-step explanation:

Let the cost per kg of B be x.

The cost of the rice will be :

Cost A = rs 66 per kg

Cost B = rs x per kg

Total cost of the two varieties :

= 12 × 66 + 16 × x

= 792 + 16x

When the two varieties are mixed the total amount of rice becomes :

= 12 + 16 = 28kg

If it is sold at the price of B the Cost will be :

= 28 × x = 28x

The profit = 28x - (792 + 16x) =

= 12x - 792

The percentage profit = 20%

20/100(792 + 16x) = 158.4 + 3.2x

This is the profit.

We equate the two as follows :

158.4 + 3.2x = 12x - 792

158.4 + 792 = 12x - 3.2x

950.4 = 8.8x

x = 950.4/8.8

x = 108

The price of B per kg is :

Rs 108 per kg.

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