A trai starts from rest travels with a uniform acceleration aquire a velecity of 60km/hr in 2minute . Find the acceleration and distance travelled in this time?
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60 kmph = 60 × 5/18 m/s = 300/18 m/s
a = v/t
= (300/18 m/s) / (2 × 60 s)
= 300 / (18 × 120) m/s²
= 0.138 m/s²
Acceleration of train is 0.138 m/s²
S = 0.5at²
= 0.5 × 300 / (18 × 120) m/s² × (2 × 60 s)²
= 1000 m
= 1 km
Distance travelled in this time is 1 km
a = v/t
= (300/18 m/s) / (2 × 60 s)
= 300 / (18 × 120) m/s²
= 0.138 m/s²
Acceleration of train is 0.138 m/s²
S = 0.5at²
= 0.5 × 300 / (18 × 120) m/s² × (2 × 60 s)²
= 1000 m
= 1 km
Distance travelled in this time is 1 km
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