Math, asked by naveen1046, 5 months ago

a train 100 m long completely passes a man walking with the same direction at 6km/h in 5 sec and a car traveling in the same direction in 6 sec at what spped was car traveling​

Answers

Answered by darksoul3
24

A train 100 meter long completely passes a man walking in the same direction at 6 km/h in 5 seconds. (x = train)

5 = 100×18 / (x-6)×5

=> 5 = 1800 / (x-6)×5

=> 5 = 1800 / 5x-30

=> 25x - 150 = 1800

=> 25x = 1950

=> x = 78

A car travelling in the same direction in 6 seconds. (y = car)

6 = 100×18 / (x-y)×5

=> 6 = 1800 / (78-y)×5

=> 6 = 1800 / 390-5y

=> 2340 - 30 y = 1800

=> -30y = 1800 - 2340

=> -30y = -540

=> y = 18

Answered by usjadhav2001
3

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ans ,18

Step-by-step explanation:

5 = 100*18 / (x-6)*5

=> 5 = 1800 / (x-6)*5

=> 5 = 1800 / 5x-30

=> 25x - 150 = 1800

=> 25x = 1950

=> x = 78

A car travelling in the same direction in 6

seconds. (y = car)

6 = 100*18 / (x-y)*5 %3|

=> 6 = 1800 / (78-y)*5

=> 6 = 1800 / 390-5y

=> 2340 - 30 y = 1800

=> -30y = 1800 - 2340

=> -30y = -540

=> y = 18

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