Math, asked by Sakchi01, 1 year ago

A train 100 m long meets a man going in the opposite direction at the rate of 5 km/h and passes him in 7.2 seconds. At what rate is the train going.

Answers

Answered by ramashishsrow7lmd
4
The speed of train relative to the man is (100/7.2)m)/s.
As the speed of Man is 5km/h = (5000/3600)m/s in opposite direction Speed of train with respect to ground = (100/7.2)-(50/36) = (450/36)m/s = 45km/h

Sakchi01: Answer is 45 not 55
ramashishsrow7lmd: wait I am checking
ramashishsrow7lmd: Sorry the man is going in opposite direction that's why we have to subtract his speed
Sakchi01: Ok sure
Sakchi01: We d
ramashishsrow7lmd: ???
Sakchi01: we add speeds when person goes in opposite directions
ramashishsrow7lmd: No we subtract we add when is same direction
Sakchi01: No its written in my book
ramashishsrow7lmd: It's wrong wriiten in your Book think it like if you will run in same direction in that of that body its speed resembles to be slow that actual speed so for the actual speed u have to add your speed and same in vice-versa
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