A train 100 meters long completely passes a man walking at 6 kmph in the same direction in 5 seconds and a car travelling in the same direction in 6 seconds. At what speed was the car travelling?
Answers
Answer: Ans: 18 km/h
Explanation:
Solution:
A train 100 meter long completely passes a man walking in the same direction at 6 km/h in 5 seconds. (x = train)
5 = 100*18 / (x-6)*5
=> 5 = 1800 / (x-6)*5
=> 5 = 1800 / 5x-30
=> 25x - 150 = 1800
=> 25x = 1950
=> x = 78
A car travelling in the same direction in 6 seconds. (y = car)
6 = 100*18 / (x-y)*5
=> 6 = 1800 / (78-y)*5
=> 6 = 1800 / 390-5y
=> 2340 - 30 y = 1800
=> -30y = 1800 - 2340
=> -30y = -540
=> y = 18
HEYA MATE.......
Find the speed in the relation to the man in meters/sec100/9 = 1l.11 m/secIn km/h: %28%283600%2A11.11%29%29%2F1000 = 40 km/h in relation to the manWho is walking at 2 km/h, therefore Actual train speed is 42 km/h:and a car traveling in opposite direction in 3 second at what speed was the car traveling?:Find the speed in relation to the car: 100/3 = 33.3 m/secIn km/h: %28%283600%2A33.33%29%29%2F1000 = 120 km/hrSince the train (42 km/hr) and car (s) are going in the opposite direction, their relative speed is the sum of the car speed and the train speeds + 42 = 120s = 120 - 42s = 78 km/hr is the actual speed of the car .
HOPE IT HELPS.......