Physics, asked by mayank1iscrazy, 5 months ago

A train 100m long is movingwith velocity of 72km/hr How much time it take to cross 1km bridge​

Answers

Answered by Skyllen
5

Given:-

  • Length of train = 100m
  • Speed/velocity of train = 72km/hr
  • Length of bridge = 1km.

To Find:-

  • Time taken by train to cross the bridge.

Solution :-

Total distance to cross the bridge will be,

⇒ Total distance = 1km + 100m

⇒ Total distance = 1000m + 100m

⇒ Total distance = 1100m

Speed of train,

= 72km/h

= 72×1000/60×60 m/s

= 72000/3600 m/s

= 20m/s

Time = Distance/Speed

⇒Time = 1100m /20m/s

⇒Time = 55 s

Therefore, time taken by the train to cross the bridge is 55 seconds.

Answered by iTzShInNy
5

  \huge\sf ➲{\underline{ \underline \color{darkgreen}{Given}}} \\  \\  \ast \:  \:  \bf Length  \: of  \: the \: train \:  \longrightarrow  \:\red{ 100  \: m} \\  \\

 \ast \:  \:  \bf Velocity  \:or  \: speed  \:  of  \: the \: train \:  \longrightarrow  \:\red{ 72 \: km/  \: h} \\  \\

 \:  \ast \:  \:  \bf Length  \: of  \: the \: bridge \:  \longrightarrow  \:\red{ 1 \: km} \\  \\

  \huge\sf ➲{\underline{ \underline \color{darkgreen}{To \:  find \: }}} \\  \\  \\  \ast \:  \:  \bf Time \:  taken  \: by \: the \: train \: to  \: cross \: the \: bridge \longrightarrow  \: \large\red{ ?} \\  \\  \\

 \:   \huge\sf ➲{\underline{ \underline \color{darkgreen}{Solution}}} \\  \\  \\ \tt Total \: distance \: to  \: cross \: the  \: bridge- \\  \\  {\boxed{ \bf NOTE:-}} \\  \\   \large\bigstar  {\underline{ \overline{ \bf 1  \: km \: =  \: 1000 \:  m}}} \bigstar \\  \\  \\

 \large \bf{➯Total  \: distance \:= \: Length \: of \:  the  \: train  +  \: Length  \: of  \: the \: bridge} \\  \\

\large \bf{➯Total  \: distance \:= \: (100 +  \: 1000) m} \\  \\

\large \bf{➯Total  \: distance \:= \:1100  \: m} \\  \\

 \\  \tt \: \: Now,  \: we \:   \: will  \: \: find \: the \: \:  speed   \: \: of  \: the  \: train \:  \\  \\

\large \bf{➯Speed \:= \: 72 \:  km/h} \\  \\

\large \bf{➯Speed \:=  \frac{72 \times 1000 \: m}{60 \times 60 \:  \:  \:  \:  \: s} } \\  \\

\large \bf{➯Speed \:= \:  \frac{720  \cancel{0} \cancel{0} \: m}{36 \cancel0 \cancel0 \: \:  \:  \:  s} } \\  \\

\large \bf{➯Speed \:= \: 20  \: m/s } \\  \\

  \\ \tt \: Now,  \: we \: \:  will \: \:  find  \:  \: the \: \:  time  \: \: taken \: by \: applying \: the \: formula -

\bigstar {\underline {\boxed { \bf  {\green\:{ \red{ Time}= \frac{ \purple{Distance}}{ \green{Speed}}   }}}}} \bigstar

  \longrightarrow{ \bf  {\green\:{ \red{  \large \: Time}=  \large\frac{ \purple{ \large110 \cancel0 \: \cancel{m}}}{  \large\green{2 \cancel0 \: \cancel{m}/s}}   }}}  \\  \\

 \longrightarrow {\underline {\boxed { \bf  {\green\:{ \red{ Time}{ = 55 s  } }}}}} \\  \\

 \large \bf \therefore \: it \: will \: take \: 55 \: seconds \: to \: cross \: the \: bridge

\\  \bigstar{ \underline{ \underline  \pink{  \sf★@iTzShInNy☆}}} \bigstar \\  \\

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