Question

a train 100m long travelling at 60 km h passes another train twice as this train and travelling in opposite direction in 10 seconds find length of second train​

Answer 1

Answer:

Total D = 100+100 = 200m

Time = 10 sec

speed = 200/10 = 20m/s = 20*18/5 = 72km/h

speed of second train = 72-60 = 12km/h (Ans)

Answer 2

Given that the speed of the first train is 60 km per hour.

Converting the speed of train to meter per second.

Therefore,

$60 km/hr=60 \times \frac{5}{18} \ m/sec\\= \frac{50}{3} \ m/sec$

Let the length of the second train is $x$ meter.

The total distance covered by the first train is

$100+100+x\\=200+x$ meter

Total time has taken 10 seconds.

According to the question

$\frac{100+x}{10}=\frac{50}{3}\\\Rightarrow 300+3x=500\\\Rightarrow 3x = 500-300\\\Rightarrow x=\frac{200}{3}$

Therefore, the length of second train is $\frac{200}{3}$ meter.

To learn more about velocity from the given link

https://brainly.in/question/769331

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