Question

A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m
long coming
from opposite direction in 6 seconds. The speed of the second train is?
​

Answer 1

Answer:

82 km/hr

Step-by-step explanation:

Given-

speed of first train =50km/hr=50×5/18 m/sec

length of first train, L1=108 m

length of second train,L2=112m

solution-

Total distance =L1+L2=108m+112m=220 m

Time taken =6sec

Relative speed =speed of first train + speed of

second train

=50×5/18 + y

=220/6

125/9 + y = 110/3

cross multiplying,we get

3(125+9y)=110×9

375+27y=990

27y=990-375

27y=615

y=615/27 m/sec

to get speed in km/hr × (18/5)

y=(615/27)×(18/5)

y=82 km/hr