A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
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Let the speed of the second train be x km/hr.
Relative speed= (x + 50) km/hr=(x + 50) x5m/sec18=250 + 5xm/sec.18Distance covered = (108 + 112) = 220 m.
220= 6250 + 5x18250 + 5x = 660
x = 82 km/hr.
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