A Train 110m long moving at speed of 45 km/hr crosses a train 90m long coming from opposite direction in 10sec . Find the speed of second train.
Answers
Answered by
2
Answer:
27 km/h
Step-by-step explanation:
Find the total distance:
Total distance = 110 + 90
Total distance = 200 m = 0.2 km
Find the total time taken:
Total time = 10sec = 1/360 h
Find their total speed:
Speed = Distance ÷ time
Speed = 0.2 ÷ 1/360 = 72 km/h
Find the speed of the second train:
Speed = 72 - 45 = 27 km/h
Answer: The speed of the other train is 27 km/h
Answered by
3
Let there are two train A and B.
length of train A , L = 110m
speed of train A , V = 45km/h = 45 × 5/18 m/s
V = 12.5 m/s
length of train B, l = 90m
Let speed of train B is v
A/C to question,
Train A crosses tran B in 10 sec
so, relative speed = ( length of train A + length of train B)/time taken
= (110 m + 90m)/10 = 20m/s
here, both trains are moving in just opposite direction.
so, relative speed = speed of train A + speed of train B
20m/s = 12.5 m/s + speed of train B
so, speed of train B = 7.5 m/s
length of train A , L = 110m
speed of train A , V = 45km/h = 45 × 5/18 m/s
V = 12.5 m/s
length of train B, l = 90m
Let speed of train B is v
A/C to question,
Train A crosses tran B in 10 sec
so, relative speed = ( length of train A + length of train B)/time taken
= (110 m + 90m)/10 = 20m/s
here, both trains are moving in just opposite direction.
so, relative speed = speed of train A + speed of train B
20m/s = 12.5 m/s + speed of train B
so, speed of train B = 7.5 m/s
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