Question

A train 120 meters long is running with a speed of 60 km/hr. In what time will it pass a boy
who is running at 6 km/hr in the direction opposite to that in which the train is going?
V​

Answer 1

Answer:

6.5 s.

Step-by-step explanation:

60 km/hr = 100/6 m/s

60 km/hr = 10/6 m/s

time = 120 ÷110/6 = 72/11 = 6.5 s.

Answer 2

Conclusion:

Train will pass the boy in $\frac{72}{11} sec$

Step-by-step explanation:

Given that, Train's length $= \textrm{120 metre}$

                  Train's speed  $= {60 \frac{Km}{hr}}$

                                           $= {60 \times \frac{1000}{3600}}$              

                                           $= \frac{50}{3} \frac{m}{sec}$

Boy's speed $= {6 \frac{Km}{hr}}$

                     $= {6 \times \frac{1000}{3600} \frac{m}{sec}}$

                     $= \frac{5}{3} \frac{m}{sec}$

Byb relative speed rule total speed $= \frac{50}{3} +\frac{5}{3} = \frac{55}{3}$

Time to pass the boy $= \frac{Distance}{speed}$

                                   $= \dfrac{120}{\frac{55}{3}}$

                                   $= \frac{72}{11} sec$