A train 120 meters long passes an electric pole in 12 seconds and another train of same length traveling in opposite direction in 8 seconds. The speed of the second train is
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Answered by
2
s1=d/t1
s1=120/12=10m/s
s2=d/t2
s2=120/8=15m/s
1 metre per second =
3.6 kilometres per hour
15m/s=15*3.6
=18*3
=54kmph
mark Brainlist if correct
s1=120/12=10m/s
s2=d/t2
s2=120/8=15m/s
1 metre per second =
3.6 kilometres per hour
15m/s=15*3.6
=18*3
=54kmph
mark Brainlist if correct
than u will have to convert it using formula 1 metre per second =
3.6 kilometres per hour
3.6 kilometres per hour
i gave the ans
72
sorry ans not matching cheak one if my ans is wrong or if aans in book is misprinted. Sorry for problem
ok
what is the ans given in book
Answered by
6
speed of 1st train=120/12=10m/s
let the speed of 2nd is v
then
240/(v+10)=8
8v=160
v=20m/s = 72km/h
mark it as brainliest
let the speed of 2nd is v
then
240/(v+10)=8
8v=160
v=20m/s = 72km/h
mark it as brainliest
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