A train 125 m long passes a man running at 5km hr in the same direction in which the train is going, in 10 seconds. the speed of the train is
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let the speed of the train = xkm/h
relative speed=x-5 km/ h
=(x-5)×5/18 m/ sec
distance =125 m
time=10sec
distance =speed ×time
(x-5)×5×10/18=125
x-5=125×9/25=45
x=50
speed =50km/h
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relative speed=x-5 km/ h
=(x-5)×5/18 m/ sec
distance =125 m
time=10sec
distance =speed ×time
(x-5)×5×10/18=125
x-5=125×9/25=45
x=50
speed =50km/h
MARK AS brainliest
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