A train 150 m long completely passes a boy walking in the opposite direction at 6km/hr in 9 second. and a car travelling in the opposite direction in 6 second. Find the speed of the car.
Answers
Answer:
The length of the train = L = 150 meters
The train cross the boy walking in opposite direction
The speed of boy = s = 6 km/h
Or, The speed of boy = 1.67 m/s
The time taken by train to cross the boy = t = 9 seconds
Let The speed of the train = S m/s
According to question
∵ Distance = Speed × time
i.e Length = (S + s) × t
Or, L = (S + s) × t
Or, 150 m = (S + 1.67) m/s × 9 s
Or, 16.67 = S + 1.67
∴ S = 16.67 - 1.67
i.e S = 15 m/s
So, The speed of the train = 15 m/s = 54 km/h
Again
A car travelling in opposite direction to train
The train cross the car in time = T = 6 seconds
Let The speed of the car = x m/s
And The speed of train = S = 15 m/s
∵ Distance = Speed × time
Length = (S + x) m/s × T
Or, 150 = (15 + x) × 6
Or, 150 = 90 + 6 x
Or, 6 x = 150 - 90
Or, 6 x = 60
x = 10 m/s
So, The speed of the car = x = 10 m/s = 36 km/h
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