a train 170 m long takes 18 second to pass a tunnel at a speed of 50km per hr. find the length of the tunnel
Answers
this answer is an example of my question seeing this you can solve yours
As given
Speed of train (v)=45Km/h(v)=45Km/h
Length of train(l)=180m(l)=180m
Length of tunnel (L)=540m(L)=540m
If train enters in tunnel when it's engine enters in tunnel and leaves it when it's last Wagon leaves the tunnel.
In this way train cover Distance equals to sum of length of tunnel and train.
So Distance Covered (s)=L+l(s)=L+l
s=540m+180ms=540m+180m
s=720ms=720m
s=0.720Kms=0.720Km ( As we know that 1Km=1000m1Km=1000m)
As we know that
Speed(v)=Distance(s)Time(t)Speed(v)=Distance(s)Time(t)
Now putting these values we get
45Km/h=0.720Kmt45Km/h=0.720Kmt
t=0.720Km45Km/ht=0.720Km45Km/h
t=0.016ht=0.016h
t=0.016×60×60seconds(1h=3600sec)t=0.016×60×60seconds(1h=3600sec)
t=57.6secondt=57.6second
a/q 170+x is divided by 250/18=18then by solving it ans.=80m
Time taken by train is 57.6 seconds
Answer:
Speed of train =90 km/h and length of train =100m =0.1km
length of tunnel =300m=0.3km
Time taken to cross the tunnel completely =
90km/h
0.3km+0.1km
=
90km/h
0.4km
=
900
40
hour =0.044 hour.