Question

A train 200 m long crosses a bridge 600 m long. It enters the bridge with speed of 30 m/s and leaves it with a speed of 50 m/s. If acceleration of train is constant throughout the motion then acceleration (in m/s2) of train is

Answer 1

Answer:

The acceleration is given as,

a=2sv2−u2

=2×500(5)2−(3)2

=100016m/s2

The time taken to cross the bridge is given as,

t=av−u

=1000165−3

=125s

Thus, the time taken to cross the bridge is 125s.

Explanation:

Hope this will help u

Answer 2

Answer:

Acceleration of train is 1 m/s².

Explanation:

Given :

• Length of train is 200 m.
• Length of bridge is 600 m.
• Initial speed of train, u is 30 m/s.
• Final speed of train, v is 50 m/s.

To find :

• Acceleration of train.

Solution :

We know,

Equation of motion

• a = v² - u²/2s

[Where, a is acceleration, v is final velocity, u is initial velocity and s is distance].

Total distance, s = 200 + 600 m = 800 m.

Put values in formula:

→ a = (50)² - (30)²/ 2 × 800

→ a = 2500 - 900/1600

→ a = 1600/1600

→ a = 1

Thus, Acceleration of train is 1 m/s².