Question

A train 200m long crosses a bridge 300m long.it inters the bridge with a speed 30ms and leaves it with a speed of 50ms.what is the time taken to cross the bridge

Answer 1

Answer:

Explanation:

Here is the answer

Answer 2

Answer:125 sec

Explanation:

Initial velocity (u) = 5m/s

Final velocity (v) = 3m/s

Total distance= distance of train + path distance

=200m + 300m = 500m

Applying the formula

v²-u²=2as

3²-5² = 2×a×500

-16 = 1000a

a = -16/1000

Applying

v = u + at

3 = 5 + (-16/1000) t

-2 = -16/1000 t

1 = 8/1000 t

t = 1000/8

t = 125 sec