A train 270 m long is running at 40.5 km/hr. how much time will it take to cross the tree?
Answers
Answered by
16
Speed = D/T
Speed = 40.5 km/hr
Distance = length of train which is 270 meters
NOTE that standard unit of speed is kilometre and hrs. So, convert 270 meters into kilometers...
270 meters into kilometre
270/1000 = 0.270 kilometers
Now, Speed = D/T
40.5 km/hr = 0.270/T
T40.5 km/hr = 0.270
T = 0.270/40.5
T = 270/1000 × 10/405
T = 3/100
T = 0.03 hrs
Speed = 40.5 km/hr
Distance = length of train which is 270 meters
NOTE that standard unit of speed is kilometre and hrs. So, convert 270 meters into kilometers...
270 meters into kilometre
270/1000 = 0.270 kilometers
Now, Speed = D/T
40.5 km/hr = 0.270/T
T40.5 km/hr = 0.270
T = 0.270/40.5
T = 270/1000 × 10/405
T = 3/100
T = 0.03 hrs
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Answered by
6
Answer: 24 seconds
Step-by-step explanation:
We know that :-
speed = (distance /time)
Time=(length/speed)
Here,the distance is length of the train=270m
and,
Speed=40.5 km/he
So,
Time taken to cross the tree = length of train as width of tree is not mentioned as well as negligible
=(270)/{40.5×(5/18)}
conversion of speed from k/h to mps since length is in meters
By calculating we get 23.9 seconds
approximately 24 seconds
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