A train 2km in the first 10 minutes, 10 km in the next 10 minutes,30 km in the next 10 minutes and 60 minutes in the next 10 minutes. What type of motion is exhibited by this train? Calculate its average speed in m/s.
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The motion is acceleration.
The avg. speed = (2+10+30+60)/40 = 102/40 =2.55km/min = 2.55 ×1000/60 =42.5m/s
The avg. speed = (2+10+30+60)/40 = 102/40 =2.55km/min = 2.55 ×1000/60 =42.5m/s
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