A train 300m long is running at a speed of 90km/hr. how many seconds will itbtake to cross a 200 m long train
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HEY FRIEND..
HERE IS UR ANSWER..
Lets assume the direction conventions. Horizontal left to right is +vedirection and opposite is −ve.−ve.
Let 1st1st train be going left to right then its speed or rather say velocity
v1→=+90km/hv1→=+90km/h
So the 2nd2nd train is in opposite direction so its velocity will be
v2→=−60km/hv2→=−60km/h
Now here we are talking about relative speed. Relative speed of a with respect to b is given by
vab→=vb→−va→vab→=vb→−va→
So relative velocity of train A with respect to train B is
vab→=(−60−90)km/hvab→=(−60−90)km/h
vab→=(−150)km/hvab→=(−150)km/h
So the velocity has become 150km.150km.
Now the total distance covered by any train let train A be its length + length of train B
So total displacement has to be made s⃗ =200+300=500ms→=200+300=500m
So according to the formula vab→=sab→tvab→=sab→t
or time t=sab→vab→t=sab→vab→
t=500m150km/ht=500m150km/h
t=12sect=12sec
HOPE IT HELPS..
:) :)
HERE IS UR ANSWER..
Lets assume the direction conventions. Horizontal left to right is +vedirection and opposite is −ve.−ve.
Let 1st1st train be going left to right then its speed or rather say velocity
v1→=+90km/hv1→=+90km/h
So the 2nd2nd train is in opposite direction so its velocity will be
v2→=−60km/hv2→=−60km/h
Now here we are talking about relative speed. Relative speed of a with respect to b is given by
vab→=vb→−va→vab→=vb→−va→
So relative velocity of train A with respect to train B is
vab→=(−60−90)km/hvab→=(−60−90)km/h
vab→=(−150)km/hvab→=(−150)km/h
So the velocity has become 150km.150km.
Now the total distance covered by any train let train A be its length + length of train B
So total displacement has to be made s⃗ =200+300=500ms→=200+300=500m
So according to the formula vab→=sab→tvab→=sab→t
or time t=sab→vab→t=sab→vab→
t=500m150km/ht=500m150km/h
t=12sect=12sec
HOPE IT HELPS..
:) :)
palak1431:
nhi
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