Question

A train accelarates at 34km/h to 54km/h in 10sec. Find its accelaration

Answer 1

Answer:

Initial speed u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s

Final speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s

Time t = 10 s

Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.

Distance travelled S = ut + ½ at2 = 10 x 10 + ½ x 0.5 x 10 x 10 m = 100 + 25 = 125 m

Answer 2

Answer:

Here is your answer

Explanation:

Given

Initial Velocity = 34 km/h

Final Velocity = 54 km/h

Time = 10 Seconds

Initial Velocity = 9.44 m/s

Final Velocity = 15 m/s

Solution

Accelaration = (Final Velocity - Initial Velocity) / Time

Accelaration = (15 m/s - 9.44 m/s) / 10 Seconds

Accelaration = (5.56 m/s) / 10 Seconds

Accelaration = 0.556 ms^-2