Question

A train accelarates from9km/h to 54km/h in 20sec find acceleration the distance trave
lled by car

Answer 1

☯ GiveN :

• Initial velocity (u) = 9 km/h = 9 * 5/18 m/s = 2.5 m/s
• Final Velocity (v) = 54 km/h = 54 * 5/18 = 15 m/s

$\rule{200}{1}$

☯ To FinD :

We have to find the acceleration done by the car.

$\rule{200}{1}$

☯ SolutioN :

We know the formula to calculate the acceleration.

$\Large{\implies{\boxed{\boxed{\sf{a = \frac{v - u}{t} }}}}}$

Where,

• a is acceleration done by the car.

★ Putting Values ★

$\sf{\dashrightarrow a = \frac{15 - 2.5}{20}} \\ \\ \sf{\dashrightarrow a = \frac{12.5}{20}} \\ \\ \sf{\dashrightarrow a = 0.625} \\ \\ \Large{\implies{\boxed{\boxed{\sf{a = 0.625 \: ms^{-1} }}}}}$