Question

a train accelerate 36km/k to 72km/p on covering 50m . Calculate the acceleration of a train and time taken to cover the distance

Answer 1

INITIAL VELOCITY = 36km/h
FINAL VELOCITY= 72km/h
DISTANCE= 50metres
ACCELERATION=?
TIME=?

To find acceleration use 3rd equation of motion

i.e.
v^2 = u^2+ 2as

Substitute the values given

72^2 =36^2 + 2×a×50
5184 = 1296 + 100a

5184-1296 =100a
3888/100 = a
a= 38.88m/s^2

for finding time use 1st equation of motion

v=u+at
72 = 36 +38.88t
72-36= 38.88t
36/38.88= t
t = 0.925925.....seconds