Question

A train accelerate from 36 km/h to 54 km/h in 10 sec. Find (i) acceleration (ii) Thedistance travelled by car ( 0.5m/s , 125m)

Answer 1

Initial speed u = 36 km/h = 36 x 1000/3600 m/s = 10 m/sFinal speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/sTime t = 10 sAcceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.
Distance travelled  S = ut + ½ at2                                     = 10 x 10 + ½ x 0.5 x 10 x 10     m                                     = 100 + 25 = 125 m