Question

. A train accelerate from 36 km/h to 54 km/h in 10 sec. Find (i) acceleration (ii) The

distance travelled by car

Answer 1

1) 0.5 ms^-2
2) 125 m
these are the answer

Answer 2

A = vf - vi ÷ t
Vf = 15m/s
Vi = 10m/s
A = 15-10 ÷10
A = 5÷10
A = 0.2 m/s2


2as = vf2 - vi2
2× 0.2 s = (15)2 - (10)2
0.4 s = 225- 100
S = 125 ÷ 0.4
S = 312.5 meter

Hope it helps you ... Mark me as brainlist plzzzzzzzzzzzzzzzzz plzzz plzzzz