Question

A train accelerate from 36 kmph to 54 kmph in 10 second what is acceleration and distance​

Answer 1

Initial speed u = 36 km/h

= 36 x 1000/3600 m/s = 10 m/s

Final speed v = 54 km/h

= 54 x 1000/3600 m/s = 15 m/s

Time t = 10 s

Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.

Distance travelled S = ut + ½ at2

= 10 x 10 + ½ x 0.5 x 10 x 10 m

= 100 + 25 = 125 m

Answer 2

Answer:

Answer is 125

Explanation:

I hope it's a correct answer