A train accelerate from 36km to 72km in 20 seconds find the distance covered by the train
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initial velocity(u)=36 km/hr=10 m/s
final velocity (v)=72 km/hr=20 m/s
time (t)=20 s
so,
a=(v-u)/t=(20-10)/20=1/2 m/s^2
so,
s=(v^2-u^2)/2a
s=(400-100)/(2*1/2)
s=300 m
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final velocity (v)=72 km/hr=20 m/s
time (t)=20 s
so,
a=(v-u)/t=(20-10)/20=1/2 m/s^2
so,
s=(v^2-u^2)/2a
s=(400-100)/(2*1/2)
s=300 m
PLZ MARK IT AS BRAINLIEST...
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